The turbulent boundary layer thickness formula assumes 1 ) the flow is turbulent right from the start of the boundary layer and 2 ) the turbulent boundary layer behaves in a geometrically similar manner ( i . e . the velocity profiles are geometrically similar along the flow in the x-direction, differing only by stretching factors in y and u ( y ) ).
22.
The turbulent boundary layer thickness formula assumes 1 ) the flow is turbulent right from the start of the boundary layer and 2 ) the turbulent boundary layer behaves in a geometrically similar manner ( i . e . the velocity profiles are geometrically similar along the flow in the x-direction, differing only by stretching factors in y and u ( y ) ).
23.
Where c _ f \ approx half of the FPZ length, \ alpha _ 0 = a / D = relative initial crack length ( which is constant for geometrically similar scaling ); g ( \ alpha _ 0 ) = k ^ 2 ( \ alpha _ 0 ) = dimensionless energy release function of linear elastic fracture mechanics ( LEFM ), which brings about the effect of structure geometry; k ( \ alpha _ 0 ) = K ( \ alpha _ 0 ) b \ sqrt D / P, and K = stress intensity factor.
24.
Weibull parameter m can be experimentally identi�ed by two methods : 1 ) The values of \ sigma _ N measured on many identical specimens are used to calculate the coefficient of variation of strength, and the value of m then follows by solving Eq . ( 4 ); or 2 ) the values of \ bar { \ sigma } _ N are measured on geometrically similar specimens of several different sizes D and the slope of their linear regression in the plot of \ log \ bar { \ sigma } _ N versus \ log D gives-1 / m.
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