From the point of view of algebraic number theory it is of interest to study " normal integral bases ", where we try to replace " L " and " K " by the rings of algebraic integers they contain.
42.
Every square-free integer ( different from 0 and 1 ) defines a "'quadratic integer ring "', which is the integral domain of the algebraic integers contained in \ mathbf { Q } ( \ sqrt { D } ).
43.
Since the square root of an algebraic integer is again an algebraic integer, it is not possible to factor any nonzero nonunit algebraic integer into a finite product of irreducible elements, which implies that \ overline { \ textbf { Z } } is not Noetherian!
44.
Since the square root of an algebraic integer is again an algebraic integer, it is not possible to factor any nonzero nonunit algebraic integer into a finite product of irreducible elements, which implies that \ overline { \ textbf { Z } } is not Noetherian!
45.
Since the square root of an algebraic integer is again an algebraic integer, it is not possible to factor any nonzero nonunit algebraic integer into a finite product of irreducible elements, which implies that \ overline { \ textbf { Z } } is not Noetherian!
46.
In Algebraic number theory, an "'algebraic integer "'is a complex number that is a root of some monic polynomial ( a polynomial whose leading coefficient is 1 ) with coefficients in \ mathbb { Z } ( the set of integers ).
47.
The special case of an integral element of greatest interest in number theory is that of complex numbers integral over "'Z "'; in this context, they are usually called algebraic integers ( e . g ., \ sqrt { 2 } ).
48.
This property stems from the fact that for each " n ", the sum of " n " th powers of an algebraic integer " x " and its conjugates is exactly an integer; this follows from an application of Newton's identities.
49.
However, if " R " is the ring of algebraic integers in an algebraic number field, or more generally a Dedekind domain, the multiplication defined above turns the set of fractional ideal classes into an abelian group, the "'ideal class group "'of " R ".
50.
It was shown that while rings of algebraic integers do not always have unique factorization into primes ( because they need not be principal ideal domains ), they do have the property that every proper ideal admits a unique factorization as a product of prime ideals ( that is, every ring of algebraic integers is a Dedekind domain ).
How to say algebraic integer in Hindi and what is the meaning of algebraic integer in Hindi? algebraic integer Hindi meaning, translation, pronunciation, synonyms and example sentences are provided by Hindlish.com.