1. That can be determined by evaluating the quadratic term of a divided difference formula. 2. At high frequencies the quadratic term becomes important. 3. Quadratic terms in and arise, which give masses to the W and Z bosons:4. Subtracting one equation from another eliminates these quadratic terms , leaving only the linear ones. 5. Since each vibrational modes contributes to two quadratic terms in the Hamiltonian, you get: 6. Partial pivoting adds only a quadratic term ; this is not the case for full pivoting. 7. The spatial symmetry of the problem is responsible for canceling the quadratic term of the expansion. 8. In fact, this is the origin of the quadratic term in the field strength tensor. 9. The same behavior can be obtained from the functional integrals, omitting the quadratic terms in the action. 10. Lord Rayleigh investigated this first and quantified the magnetization M as a linear and quadratic term in the field:
