finite measure sentence in Hindi
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- For the duality between ?-finite measure spaces and commutative von Neumann algebras, noncommutative von Neumann algebras are called " non-commutative measure spaces ".
- For some non-negative finite measure ? on the circle : in this case, if non-zero, ? must be singular with respect to Lebesgue measure.
- More generally the transition rates are given in form of a finite measure c _ \ Lambda ( \ eta, d \ xi ) on S ^ \ Lambda.
- The theorem states that if a uniformly bounded sequence of functions converges pointwise, then their integrals on a set of finite measure converge to the integral of the limit function.
- This condition is also necessary if \ mathcal { T } contains all singleton sets and F is required to be a single crossing function for any finite measure \ mu.
- Analogously, a set in a measure space is said to have a " ?-finite measure " if it is a countable union of sets with finite measure.
- Analogously, a set in a measure space is said to have a " ?-finite measure " if it is a countable union of sets with finite measure.
- An abstract Wiener space is a mathematical object in measure theory, used to construct a " decent ", strictly positive and locally finite measure on an infinite-dimensional vector space.
- A Borel measure ? on X is boundedly finite if ? ( A ) M _ X be the space of all boundedly finite measures on \ mathfrak { B } ( X ).
- Nonzero finite measures are analogous to probability measures in the sense that any finite measure is proportional to the probability measure \ frac { 1 } { \ mu ( X ) } \ mu.
- Nonzero finite measures are analogous to probability measures in the sense that any finite measure is proportional to the probability measure \ frac { 1 } { \ mu ( X ) } \ mu.
- This measure space is not ?-finite, because every set with finite measure contains only finitely many points, and it would take uncountably many such sets to cover the entire real line.
- The Banach space " B " has "'the Radon Nikodym property "'if " B " has the Radon Nikodym property with respect to every finite measure.
- The Fourier Stieltjes transform of a finite measure \ mu on \ widehat { \ mathit { G } } is the function \ widehat { \ mu } on \ mathit { G } defined by
- The former gives almost surely positive and \ sigma-finite measure to the Brownian path in \ scriptstyle \ mathbb { R } ^ n when n > 2, and the latter when n = 2.
- This measure is not " ? "-finite, because every set with finite measure contains only finitely many points, and it would take uncountably many such sets to cover the entire real line.
- Since " X " is not measurable for any rotation-invariant countably additive finite measure on " S ", finding an algorithm to select a point in each orbit requires the axiom of choice.
- Suppose that " X " is the first uncountable ordinal, with the finite measure where the measurable sets are either countable ( with measure 0 ) or the sets of countable complement ( with measure 1 ).
- In that case, " ? " has to be a finite measure, and the lattice condition has to be defined using cylinder events; see, e . g ., Section 2.2 of.
- Maybe an easier example of a non-sigma finite measure space would be an uncountable set given the counting measure ( the measure of a subset here is simply its talk ) 09 : 00, 10 December 2008 ( UTC)
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